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What is the role of the AND gates in the following circuit? To perform a 1-bit multiplication per AND gate I have no idea To block the signal flow when not wanted To act as part of the multiplexer array

          What is the role of the AND gates in the following circuit?
To perform a 1-bit multiplication per AND gate
I have no idea
To block the signal flow when not wanted
To act as part of the multiplexer array
        
What is the role of the AND gates in the following circuit?
To perform a 1-bit multiplication per AND gate
I have no idea
To block the signal flow when not wanted
To act as part of the multiplexer array

Added by Megan R.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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What is the role of the AND gates in the following circuit? To perform a 1-bit multiplication per AND gate I have no idea To block the signal flow when not wanted To act as part of the multiplexer array What is the role of the AND gates in the following circuit? FA m FA FA FA P6 ps O To perform a 1-bit multiplication per AND gate OI have no idea O To block the signal flow when not wanted O To act as part of the multiplexer array
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A multiplexer is a switching circuit that produces as output one of a set of input bits based on the value of control bits. Construct a multiplexer using AND gates, OR gates, and inverters that has as input the four bits $x_{0}, x_{1}, x_{2},$ and $x_{3}$ and the two control bits $c_{0}$ and $c_{1} .$ Set up the circuit so that $x_{i}$ is the output, where $i$ is the value of the two-bit integer $\left(c_{1} c_{0}\right)_{2} .$

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Transcript

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00:01 Hi, in this question we have to derive the full ladder using basic gates.
00:06 So here we are given with inputs a, b, c, sum and carry.
00:13 So here it's 00, 0, 00, so then 001, 10, then 010, 10, then 011 and 01 and then we have 10010 and we have 101 and 110 and 111.
00:38 So here we have sum is 01, 01 and 11.
00:44 So this is the truth table.
00:46 So this is the k -map for the given problem.
00:48 So here we have sum is given by a plus b plus c in and we have carry is given by, so it is a b plus b c in plus a c in.
01:01 Now we have, so the circuit is given by, so here we can use xor gate.
01:08 So xor gate, so xor gate.
01:14 So here we have a, b and here we have a plus of b and c in and here we have a plus b plus c in and this is sum.
01:28 Then we have the gate for carry.
01:30 So here we have and gate.
01:32 So and gate of a, b.
01:36 So this is a, b.
01:37 Then we have b and c in.
01:40 So here we have another and gate, b and c in...
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