00:01
So over here we're asked what is going to be the solubility of a gcl, which is going to have a solubility product constant equal to 1 .6 times 10 to the minus 10 in a solution, which is going to be 8 .8 times 10 to the minus 2 molar in sodium chloride.
00:24
That means that the concentration of the chlorine ion in solution is going to be equal to 8 .8 times 10 to the minus 2.
00:31
So in this case, the reaction that we're going to consider is going to be the dissolution of the solid going into silver plus plus cl minus.
00:44
We're going to write down an ice table equivalent for this task, in this case a certain amount equal to the solubility is going to dissolve and initially we're going to have zero silver plus and 8 .8 times 10 to the minus 2 in the concentration of cl minus.
01:01
Thus, the amount of change would be equal to the solubility of the compound, so at equilibrium the solid doesn't matter, but we're going to get solubility of silver plus and 8 .8 times 10 to the minus 2 plus solubility of cl minus.
01:19
Thus, the solubility product constant, which is equal to the product of ag plus times the the product of cl - would be equal to s times 8 .8 times 10 to the minus 2 plus s.
01:36
Over here, we could go ahead and perform an approximation, assuming that solubility will be much smaller than 8 .8 times 10 to the minus 2.
01:53
The result over here should be equal to our solubility product constant.
01:57
Over here, we're based on the fact that the solubility product constant is in the order of 10 to the minus 10, so we expect the value for solubility to be at least on the order of 10 to the minus 5, if not to be smaller.
02:10
So first we're going to solve the problem with this approximation, and then we're going to solve the full quadratic expression.
02:16
So under this approximation, the value for solubility would be equal to, the solubility would come from the following expression.
02:28
If this is true, 8 .8 times 10 to to the minus 2 plus s is going to be approximately 8 .8 times 10 to the minus 2...