00:01
We need to find the solution to the system.
00:02
So we're going to solve this equation for x.
00:04
So we get 14 minus 3z.
00:07
We're going to replace that into both the first equation and the second equation.
00:12
So we get 2 times the quantity 14 minus 3z plus y minus z is equal to 5.
00:22
So that becomes 28 minus 6z plus y minus z is equal to 5.
00:28
So this is y minus 7 z is equal to.
00:33
We move the 28 over.
00:35
So 5 minus 28 is negative 23.
00:39
We do the same thing with the second one.
00:40
So negative 2 times a quantity 14 minus 3z minus 3y plus 2z is equal to 2.
00:47
This becomes negative 28 plus 6z minus 3y plus 2z is equal to 2.
00:55
So this becomes negative 3y plus 8z is equal to.
01:03
We move the 28 over, so that's equal to 30.
01:07
We multiply the top equation by 3...