00:01
For this problem we're trying to find the experimental yield or actual yield right here.
00:08
If we know that our percent yield is 77 .6 percent and so you need to write out your reaction.
00:16
So iron three chloride is fecl3 lead two nitrate pbno3 parentheses two and then it's a double replacement reaction.
00:24
So feno3 parentheses three plus pbcl2.
00:29
Now this is not yet balanced but one thing to know this is your insoluble product.
00:34
This is the precipitate that you are going to make.
00:37
Lead two chloride is insoluble.
00:39
So let's go ahead and balance this.
00:41
So this is going to need a two in front of it.
00:44
This is going to need a three.
00:46
This is going to need a three and this is going to need a two.
00:50
Okay so first thing we need to do is find our moles.
00:54
So we have milliliters and molarity for each of these solutions.
00:58
So we need to take milliliters and change them to liters divide by a thousand.
01:02
So it would be 0 .0155 and then take that times the milliliter of 0 .70 and that would give you 0 .0109 moles.
01:16
That's for a coefficient of two right here.
01:19
So i'm going to go ahead and divide that by two while i'm here.
01:22
Well it's in my calculator 0 .00543 for a coefficient of one.
01:28
Okay now i'm going to do the same thing with my lead two nitrate.
01:31
I'm going to take 0 .0158 times 0 .701 and that gives me 0 .0111 moles...