What is the thinnest film of $\mathrm{MgF}_{2}(n=1.38)$ on glass that produces a strong reflection for orange light with a wavelength of $600 \mathrm{nm} ?$
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What is the thinnest film of MgF2 (n = 1.38) on glass that produces a strong reflection for light with a wavelength of 698 nm? (in nm) Your Answer: Answer
Prabhu R.
Constructive interference occurs when the path difference between two waves is equal to an integer multiple of the wavelength. To find the thinnest film of MgF2 (n = 1.39) on glass that produces strong reflection for light with a wavelength of 670 nm, we can use the formula: 2 * n * d = m * λ Where: n = refractive index of the film (1.39) d = thickness of the film m = order of the interference (in this case, we want the first order, so m = 1) λ = wavelength of light (670 nm) By rearranging the formula, we can solve for d: d = (m * λ) / (2 * n) Plugging in the values, we get: d = (1 * 670 nm) / (2 * 1.39) Simplifying the expression, we find: d ≈ 241.01 nm Therefore, the thinnest film of MgF2 on glass that produces strong reflection for light with a wavelength of 670 nm is approximately 241.01 nm thick.
Sri K.
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