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Hello students, in this question a 10 g of ice has been converted to a steam at 100 degrees celsius.
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It goes through the following process.
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Initially the ice at 0 degree celsius melt to become liquid at 0 degree celsius.
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Here the latent heat plays a role and here the liquid at 0 degree celsius is heated to 100 degree celsius.
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Here the specific heat will play a role and again here the liquid at 100 degree celsius is vaporized to steam.
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So, that here the latent heat will play a role.
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So, we have to find out the q that is the heat associated with this process.
00:38
So, at first we are going to find out the heat associated for the conversion of ice at 0 degree celsius to liquid at 0 degree celsius.
00:47
So, this is given by the formula q is equal to n into del h of fusion.
00:53
So n is given by the mass divided by molar mass.
00:59
Substituting the in this equation mass divided by molar mass into del h of fusion, substituting the values, the mass of the ice is 10 g divided by the molar mass of the water is 18 g per mole into del h of fusion is 6 .01 kj per mole.
01:17
On solving this we will find out the q associated with this will be equal to 3 .342 kj.
01:26
Coming to the second conversion that is the liquid at 0 degree celsius is heated to the liquid at 100 degree celsius...