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What is the total volume of the mixture of hydrogen gas and oxygen gas can be obtained from the electrolysis of 205.8 grams of water (molecular weight 18.015 g mol?¹) at 25.0 °C and 1.00 atm pressure according to the chemical equation shown below? 2 H?O(l) ? 2 H?(g) + O?(g) 

          What is the total volume of the mixture of hydrogen gas and oxygen gas can be obtained from the electrolysis of 205.8 grams of water (molecular weight 18.015 g mol?¹) at 25.0 °C and 1.00 atm pressure according to the chemical equation shown below?

2 H?O(l) ? 2 H?(g) + O?(g)
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What is the total volume of the mixture of hydrogen gas and oxygen gas can be obtained from the electrolysis of 205.8 grams of water (molecular weight 18.015 g mol?¹) at 25.0 °C and 1.00 atm pressure according to the chemical equation shown below? 2 H?O(l) ? 2 H?(g) + O?(g)

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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What is the total volume of the mixture of hydrogen gas and oxygen gas can be obtained from the electrolysis of 205.8 grams of water (molecular weight 18.015 g mol-1) at 25.0 °C and 1.00 atm pressure according to the chemical equation shown below? 2 H2O(l) → 2 H2(g) + O2(g)
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Transcript

-
00:01 Here the formation of hydrogen and oxygen gas from water is given.
00:06 So the question the weight of hydroge water is given 205 .8 grams.
00:16 So this much gram of water is used the reaction.
00:20 So we convert this gram into moles of water.
00:23 So mole of h2o will equal to its weights that is 205 .8 gram divide by its molar mass.
00:31 That is 18 gram per which will give 11 .42 all.
00:38 Now from equation it is clear that 2 mole of water produce equal number of hydrogen gas that is 2 mole of h2o...
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