What is the value of the cross-correction $r_{xh}(\tau)$ between the following two functions at the lag position of $\tau = 3$: $x(t) = 3 \text{ rect}((t-2)/4)$ $h(t) = -5 \text{ rect}((t-1)/2)$ $r_{xh}(3) = ?$ O -45 O -30 O -15 O 0 O 15 O 30 O 45
Added by Joseph S.
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So, we need to compute: $$r_{xh}(3) = \int_{-\infty}^{\infty} 3 \text{ rect}((t-2)/4) \cdot (-5) \text{ rect}((t-1-3)/2) dt$$ $$r_{xh}(3) = -15 \int_{-\infty}^{\infty} \text{ rect}((t-2)/4) \text{ rect}((t-4)/2) dt$$ Show more…
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