what isthe probability that the total of two dice will be greater than 9 given that the first di

Step 1: Identify the possible outcomes for the second die. Since the first die is a 6, the secon

What isthe probability that the total of two dice will be...

Transcript

00:01 I'm a teacher for this question and our question says that if two fair dyes are rolled find the probability that the sum of the dice is six given that the sum is greater than five how we're going to solve this question just see that if two fair dyes are rolled find the probability that the sum of the dice is six we need to find the probability that some of the dice is six so i'll be writing this event so some of the dice is six is having the elements as 15243 4251 so these are the six elements and the probability here is six sorry five one all right so this is five elements only right these are the one two three four five five elements five by 36 then and after we're gonna write that given that the sum is greater than five so some is greater than five so some is greater than five since the sum is greater than five then the sum can be six so six will have if these five outcomes all right like one five one five two four three three four two five one then after seven is a sum so one six 25 3 4 4 3 5 2 6 1 then and after 8 so for 8 you will be writing this as 2 6 2 6 all right sum is greater than 5 so i'll be writing for 8 9 10 and 12 also all right so i'll be writing all the outcomes here so 2 6 3 5 4 4 5 3 6 then and after 9 so for 9 you will be writing 3 6 4 5 5 4 6 3 this is 9 for 10 you will be writing that 4 6 5 5 5 6 4 4 4 then you will be writing that 4 6 5 5 6 4 4 4 then for 11 you will be writing 5 -6 -65 then after 6 6 all right so you'll be having that 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 17 17 18 19 20 21 22 20 3 24 25 26 all right so that will be 26 by 36 so i'll be writing this as 13 by 18 but what we need to find that is given that the sum is greater than 5 we need to find the probability of getting on the dice 6 all right so i'll be writing that probability of this is given that sum is greater than 5 so given that sum is greater than 5 that is the event let's say b and let's say this is the event a so i'll be writing that a intersection b will have a as the element so you will be writing c probability of a by b given that b is already happened so you'll be writing probability of a intersection b divided by probability of b so you'll be writing a intersection b is here a intersection b for this particular problem is a so we'll be writing this as probability of a divided by probability of b so i'll be writing that 5 by 36 divided by 13 by 18 5 by 36 divided by 13 by 18.

04:23 So you'll be writing that 18, 2s are 36.

04:25 So 5 .13 to 2 are 26.

04:28 So 5 by 26...