What mass of barium sulfate will be produced when 12.0 grams of barium chloride reacts with an excess of sodium sulfate? BaCl2 + Na2SO4 -> BaSO4 + 2 NaCl
Added by Dustin M.
Step 1
The balanced equation is already given: BaCl2 + Na2SO4 -> BaSO4 + 2 NaCl. This tells us that one mole of barium chloride reacts with one mole of sodium sulfate to produce one mole of barium sulfate and two moles of sodium chloride. Show more…
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