What mass of KCIO3 must be decomposed to produce 126L of oxygen gas at 133 degrees celcius and 0.880 atm?
Added by Alexander C.
Step 1
First, we need to find the moles of oxygen gas produced. We can use the ideal gas law for this: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Show more…
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A common laboratory method for preparing oxygen gas involves decomposing potassium chlorate (KClO3), as shown by the reaction. 2 KClO3 → 2 KCl + 3 O2 Based on this equation, how many grams of KClO3 must be decomposed to produce 1.95 mol KCl? mass: g KClO3 How many grams of KClO3 must be decomposed to produce 59.7 g O2? mass: g KClO3
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What mass of $\mathrm{KNO}_{3}$ would have to be decomposed to produce $21.1 \mathrm{~L}$ of oxygen measured at $\mathrm{STP}$ ? $$2 \mathrm{KNO}_{3}(\mathrm{~s}) \stackrel{\text { heat }}{\longrightarrow} 2 \mathrm{KNO}_{2}(\mathrm{~s})+\mathrm{O}_{2}(\mathrm{~g})$$
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