00:01
Hello, my name is john, and for this question, what mass of sodium benzodia should be added to 400 milliliters of 1 .00 molarity of benzoic acid to produce a buffer solution with a ph value of 3 .5? we can assume that there is no volume change when sodium benzoy is added to benzodia acid.
00:20
So, for this question, we're going to use the formula ph is equal to the pk value plus log of the concentration of the base.
00:31
Over the concentration of the conjugate acid.
00:38
So all i have to do is plug in the numbers.
00:41
So we have 3 .5 as a ph value.
00:44
As we should probably know, pca is equal to the negative log of the ca value, which was given, plus the log of.
01:01
So since they share the same volume, we're going to simply put 1 .00 molarity, which was given for the conjugate acid.
01:12
And we're trying to find the concentration of sodium benzoy, which is the base...