What particle is produced in the following decay: 29^77Cu⟶30^77Zn+? alpha particle: 2^4α positron: +1^0β neutron: 0^1n beta particle: −1^0β
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The initial particle is \( ^{77}_{29}Cu \) (Copper-77) and the final particle is \( ^{77}_{30}Zn \) (Zinc-77). Show more…
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