Question

What quantity in moles of NH₃ gas forms when 32.4 L of H₂ gas completely reacts at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. 1 N₂(g) + 3 H₂(g) → 2 NH₃(g)

          What quantity in moles of NH₃ gas forms when 32.4 L of H₂ gas completely reacts at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. 1 N₂(g) + 3 H₂(g) → 2 NH₃(g)
        

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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What quantity in moles of NH₃ gas forms when 32.4 L of H₂ gas completely reacts at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. 1 N₂(g) + 3 H₂(g) → 2 NH₃(g)
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How many moles of NH₃ form when 32.4 L of H₂ gas completely reacts at STP according to the following reaction? Remember, 1 mol of an ideal gas has a volume of 22.4 L at STP. N₂(g) + 3 H₂(g) → 2 NH₃(g)

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Transcript

-
00:01 Firstly, let's summarize this problem.
00:06 Volume of hydrogen gas equals 32 .4 liters.
00:13 And the task is to find the number of moles of ammonia.
00:22 Firstly, let's rewrite reaction equation.
00:26 Nitrogen gas plus three molecules of hydrogen gas equals two molecules of ammonia.
00:37 Let's remind that at standard temperature and pressure, one more of an ideal gas occupies 22 .4 liters.
00:53 But in this case we have 32 .4 liters...
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