00:01
To determine the quantity of energy produced when one gram of plutonium undergoes alpha decay, to produce uranium 234, we need to know how much energy is released when just one nucleide of this undergoes the decay first.
00:19
So if one nucleide undergoes the decay, we're going to calculate the mass difference, which will be the mass of the products, an alpha particle.
00:38
4 .00260 amu plus the mass of the product uranium 234 to 34.
00:51
34 .49 minus the mass of plutonium 238, 239, 20495 amu.
01:08
And we get 0 .006 amu.
01:15
As the mass difference.
01:18
So now let's figure out how many plutonium 238 nucleides are in one gram.
01:25
This being the mass difference per one nucleide.
01:30
1 gram, plutonium 238, can be converted into number of nucleides by first converting to amus using avogadro's number.
01:51
1 gram is 6 .0222.
01:55
Times 10 to the 23rd amu, and then there are 238 .0495 amu in one nucleide.
02:12
Now that we know the number of uranium, sorry, plutonium, 238 nucleides in one gram, and this being the mass defect per nucleide, then we can calculate the total mass defect.
02:28
One nucleide is 0 .006 amu...