What should be the angle above the horizontal plane at which a projectile is shot if the maximum height of it reaches is equal 1/14 of its range? State your answer in degrees to the nearest degree.
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Step 1
Step 1: Write down the given information: - Maximum height reached by the projectile = 1/14 of its range - Maximum height (H) = v^2 * sin^2(theta) / (2g) - Range (R) = v^2 * sin(2*theta) / g Show more…
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