00:01
Hi, here in this given problem there is a complicated circuit diagram, a mixed grouping of various batteries and resistors.
00:20
The circuit is having two loops, three resistors each in one branch, three batteries each in one branch of the circuit.
00:38
The uppermost battery having potential 12 volt, the middle one 3 volt, the bottom one 9 volt.
00:48
Resistance is 5 ohm, 10 ohm and 5 ohm.
00:56
So first of all using kirchhoff's junction rule, the currents, suppose current i1 is coming out of the positive terminal of the battery of voltage 12 volt, here it will be divided into two parts.
01:17
Suppose i2 goes through this 3 volt, so the remaining using junction rule, remaining will be i1 minus i2 passing through this 5 ohm and then through 9 volt.
01:30
So here at this junction the two currents will be combined again to make i1 again.
01:37
This is closed loop 1, this is closed loop 2.
01:41
So first of all using kirchhoff's loop rule in closed loop 1, the upper one, i1 passing through this 5 ohm and counter clockwise direction, so potential draw will be negative, minus 5 i1 and then i2 passing through this 10 ohm that is also counter clockwise, so minus 10 i2 is equal to 12 volt sending its current in counter clockwise direction, so minus 12, 3 volt that is also sending its current in counter clockwise direction, so minus 3.
02:39
So rearranging the terms we get i1 plus 2 i2 is equal to 3...