00:01
In this problem, we have been given the system of capacitors which are connected as shown, and c1 here is having capacitance 0 .6 microferrin, and c2, that is having capacitance 10 microferrin.
00:18
And it's given to us that the energy which is stored in this 2 .5 microferret capacitor, that is 1 .8 times 10 raise to minus 4 joules.
00:29
And we are required to determine the total energy which is stored in the capacitors c1 and c2.
00:39
So here let's combine these two capacitors.
00:42
So as they are connected in series, we have to find their equivalent capacitance, which is given by the expression 1 by c equals 1 by 0 .6 plus 1 by 10.
00:54
And that implies their equivalent capacitance that will be 0 .6 times 10 over 10 plus 0 .6.
01:02
So when we multiply 0 .6 with 10 and divide this with 10 plus 0 .6, we're going to get here.
01:10
The equivalent capacitance coming out to be 0 .57 microferret...