00:03
Here in this problem we have to calculate the volume in milliliters of a 0 .1 to 8 molar calcium hydroxide solution that must be used to neutralize 22 .3 milliliters of 0 .37 molar phosphoric acid.
00:21
Now let's write the neutralization reaction here.
00:26
Here calcium hydroxide reacts with phosphoric acid and the products are calcium phosphate and water.
00:43
Now let's balance this equation.
00:46
Here three calcium atoms.
00:48
So to balance it, let's place three here.
00:51
Now here we have two phosphate ions on the product side.
00:56
So to balance it on the reactant side, let's place two here.
01:00
Now both sides of the equation have two phosphate ions.
01:04
We have now here six hydrogen atoms also six three times two total 12 hydrogen atoms on the reactant side.
01:13
So let's place six here to balance the number of hydrogen atoms.
01:17
Now let's count oxygen atom besides the atoms, oxygen atoms presenting phosphate group...