00:01
Hi, so we are to solve for the volume occupied by the given amount of argon gas.
00:05
And to solve the volume, we will be using the ideal gas equation pv is equivalent to nrt, where p is the pressure in terms of atm, v is the volume in terms of liters, n is the number of moles, r is the ideal gas constant, and t is the temperature.
00:22
We're given with the pressure, we have the temperature, and we know the value of r, but we don't have the number of moles instead we have the mass of argon gas so first step we will convert this amount to moles so the number of moles of argon if we have 16 .1 grams of argon we will divide here the atomic mass of argon from the periodic table that's 39 .95 grams per mole this is the atomic mass of argon from the periodic table so now we'll cancel grams and and dividing 16 .1 by 39 .95, this will give us 0 .403.
01:06
This is moles of argon.
01:08
And now let's rearrange this equation to solve for the volume.
01:12
We'll have volume is equivalent to nrt over pressure.
01:16
Now let's plug in the given information.
01:18
The number of moles we have calculated, 0 .403 moles.
01:23
The ideal gas constant is 0 .0821 liters atm per mole kelvin.
01:31
The temperature is 379 kelvin.
01:35
And then we have the pressure 1 .17 atm.
01:39
Now we'll cancel some units...