What volume (mL) of a 0.2450 M KOH(aq) solution is required to completely neutralize 55.25 mL of a 0.5440 M H3PO4(aq) solution? 165.8 mL 368.0 mL 30.06 mL 90.17 mL 22.09 mL
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Given: Volume of H3PO4 solution = 55.25 mL Concentration of H3PO4 solution = 0.5440 M Number of moles = Volume x Concentration Number of moles = 55.25 mL x 0.5440 mol/L Number of moles = 30.056 mol Show more…
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