What volume of 0.250 M KCl is needed to make 100.0 mL of 0.100 M solution?
Added by Alejandra R.
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100 M solution. Given concentration of KCl solution = 0.100 M Volume of KCl solution needed = 100.0 mL = 0.100 L Moles of KCl = Molarity x Volume Moles of KCl = 0.100 mol/L x 0.100 L Moles of KCl = 0.010 mol Show more…
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