00:01
Next question, we have to calculate volume of 10 molar sodium hydroxide needed in order to prepare buffer solution.
00:11
So what is provided is ph of buffer solution we want to prepare is 7 .79 and we are preparing buffer solution of tris -hcl.
00:21
So its reduced form is nothing but tris.
00:24
Now what is happening in tris that if this is reducing to this that means the amount of tris formed will be exactly equal to the amount of naoh because naoh is going to take h plus from tris -hcl and reduce it to the tris, sorry and h plus yeah and reduce it to the tris that means how many h plus are removed will be equal to h minus of sodium hydroxide that means this concentration will be equal.
00:50
So now further let's see what we have given.
00:53
We have been provided with amount of tris -hcl and it is given as 31 .52 grams.
00:59
So let's calculate moles.
01:01
Moles will be equal to this given mass that is 31 .52 divided by its molar mass.
01:06
Its molar mass is approximately 157 .6 gram per mole.
01:11
So number of moles we have calculated here and they are equal to 0 .2 moles.
01:17
So now what we have to do is we have to use hassell -betch, henderson -hassell -betch equation which is nothing but ph is equal to pka plus log to the base 10 reduced form of acid that is tris divided by actual acid that is tris -hcl and here we can calculate this concentration terms...