00:02
Hello, in this question we have a neutralization reaction.
00:06
In a neutralization reaction an acid reacts with a base to produce a salt and water.
00:13
Therefore the first thing i want to do is to write that balanced equation.
00:18
So we have hydrobromic acid that is going to be hbr and it is going to react with sodium hydroxide which is naoh.
00:33
Both of these are solutions so they're both aqueous.
00:41
When they react they're going to exchange ions.
00:43
So the sodium from the sodium hydroxide is going to combine with the bromide ion.
00:50
And we're going to get sodium bromide which is a salt and then our other product is going to be water which will be a liquid.
00:59
All right so this is our equation.
01:01
Looking at it we see it's already balanced as written with one bromine on each side, one sodium, one oxygen, and two hydrogen.
01:10
So this equation is already balanced and when we have a balanced equation the coefficients in the balanced equation tell us the mole ratio.
01:21
Well if there's no coefficient written it's understood to be a one just like in math class.
01:26
Therefore our mole ratio tells us that for every mole of hbr we need one mole of naoh and we will produce one mole of the sodium bromide and one mole of the water.
01:43
But we're most interested in the reactants here because we want to calculate how much of the acid we need.
01:51
We see that they're reacting in a one to one ratio.
01:56
What that means is however many moles of hbr we use we need to use the same number of moles of sodium hydroxide for this neutralization.
02:12
And furthermore we're given molarity in the problem and volume at least for the base...