What volume of sulfur dioxide is required to react with 177 liters of oxygen gas according to the following reaction? (All gases are at the same temperature and pressure.) \[ \text { sulfur dioxide }(g)+\operatorname{oxygen}(g) \rightarrow \text { sulfur trioxide }(g) \] Volume \( = \) \( \square \) L
Added by Tammy O.
Close
Step 1
The unbalanced equation is: \[ \text{sulfur dioxide (g) } + \text{ oxygen (g) } \rightarrow \text{ sulfur trioxide (g)} \] Balancing the equation, we get: \[ 2 \text{ SO}_2(g) + \text{ O}_2(g) \rightarrow 2 \text{ SO}_3(g) \] Show more…
Show all steps
Your feedback will help us improve your experience
Jital V and 67 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
What volume of oxygen is needed to react with solid sulfur to form 6.20 L of sulfur dioxide?
Shalini T.
What volume of oxygen gas reacts with 30.0 L of sulfur dioxide gas? (Assume temperature and pressure remain constant.) __SO2(g) + __O2(g) ---> __SO3(g)
Shaiju T.
If 1.25 L of sulfur dioxide gas reacts with 3.00 L of oxygen gas according to the equation in Exercise $71,$ what is the volume of sulfur trioxide gas produced? Assume all gases are at the same temperature and pressure.
Bridger J.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Watch the video solution with this free unlock.
EMAIL
PASSWORD