What volume will be occupied by 4.0 g of oxygen gas at 52°C and 0.75 atm pressure? (R = 0.0821 atm · L / mol · K) 0.71 L 142 L 4.4 L 8.9 L
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Given mass of oxygen gas (O2) = 4.0 g Molar mass of O2 = 32 g/mol Number of moles = Mass / Molar mass Number of moles = 4.0 g / 32 g/mol Number of moles = 0.125 mol Show more…
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