A submarine (sub A) travels through water at a speed of 6.00 m/s, emitting a sonar wave at a frequency of 1400 Hz. The speed of sound in water is 1533 m/s. A second submarine (sub B) is located. Both submarines are traveling directly toward each other. The second submarine is moving at 9.00 m/s. What frequency is detected by an observer riding on sub B as the subs approach each other? 1586Hz 1365Hz 2222Hz 1416Hz
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This is known as the Doppler effect. The formula for the observed frequency (f') due to the Doppler effect is: f' = (v + vo) / (v - vs) * f Where: f' is the observed frequency v is the speed of sound in air vo is the velocity of the observer vs is the velocity Show more…
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