00:01
Hi, in this question we need to give the reduction reaction between estron and sodium borohydride.
00:06
We are asked to give the mechanism, stereochemistry of main product, and we need to select the type of reaction, whether it is stereo selective reaction or stereo specific reaction.
00:16
Here is the structure of estron.
00:18
When this react with reducing agent, n -a, b -h -4, that is sodium borohydride, then there will be the formation of alcohol.
00:28
We are given with the ketone in this estron that will be reduced by nabh4 to give the alcohol.
00:36
Let us see the mechanism of reaction.
00:39
Here we are only considering this cyclicitonic part to show the reduction of this ketone to alcohol.
00:46
We can see the carbonyl compound is having carbon and oxygen double bond.
00:51
The carbon will be having delta positive charge and the oxygen will be having delta negative charge.
00:57
Here, in this nebh4, we are having bh4 minus ion.
01:03
This will give the h minus ion that is the hydride ion, since there will be the polarity between carbon and oxygen, and here this h negative will attack on this carbon positive charge...