00:02
Okay, what frequency, what will the frequency be if 0 .320 kilograms is added or subtracted to the mass, and they want you to find this without finding the force of the spring constant.
00:15
So i think there's a part of this question missing, so we're just going to kind of solve these two in general, and then based on the numbers that they gave you at the beginning of your problem, you can just plug it in and pop it into a calculator and you'll get your answer.
00:28
So it's experiencing simple harmonic motion.
00:34
So the frequency of the system is 1 over 2 pi times the square root of k over m.
00:45
So if you want to know what will the frequency be, you're changing it.
01:00
So it's like this is when it starts and then f2 is when it starts and then f2 is when it ends after you've changed it.
01:13
So if you want to know the new frequency, you can use this to find it to make it a little bit easier and so that we have a formula we can work with.
01:22
We can actually divide these two.
01:24
So we can do f1 over f2 is equal to 1 over 2 pi the square rate of k over m1 over 1 over 2 pi the square root of k over m2.
01:40
Notice that the 1 over 2 pi is cancel...