00:01
Hello students, it is given that pitch p equal to 10mm and diameter d equal to 15mm and coefficient of friction mu equal to 0 05.
00:16
For part a, we want to find that the tangential force required at the end of 300m lever to lift a load of 6 ,000 newton.
00:27
That is, tan theta equal to p.
00:31
By pi into t.
00:34
Substituting all the values here we get tan theta equal to 10 divided by pi into 50 which is equal to 0 .0 637 that is theta equal to 10 inverse of 0 .0 637 which is equal to 3 .644.
01:00
It is given that coefficient of friction mu equal to 0 .05, that is, tan 5 equal to 0 .05.
01:10
So, 5 equal to tan inverse of 0 .05, which is equal to 2 .86240.
01:21
Then the tangential force is given as, equal to d by 2r into w into 10 theta plus 5.
01:42
Substituting all the values here we get 50 divided by 2 into 300 into 6 ,000 into 10 of 3 .646 plus 2 .8624...