Question

A wheel rotates at a constant rate of 2.10 x 10^3 rev/min. (a) What is its angular velocity in radians per second? (Enter the magnitude.) 219.8 rad/s (b) Through what angle does it turn in 32 s? Express the solution in radians and degrees. in radians 122.76 rad in degrees 7033.60 °

          A wheel rotates at a constant rate of 2.10 x 10^3 rev/min.
(a) What is its angular velocity in radians per second? (Enter the magnitude.)
219.8 rad/s
(b) Through what angle does it turn in 32 s? Express the solution in radians and degrees.
in radians 122.76 rad
in degrees 7033.60 °

A wheel rotates at a constant rate of 2.10 x 10^3 rev/min.
(a) What is its angular velocity in radians per second? (Enter the magnitude.)
219.8 rad/s
(b) Through what angle does it turn in 32 s? Express the solution in radians and degrees.
in radians 122.76 rad
in degrees 7033.60 °

Added by Kathryn H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sahil Kumar

03/30/2022

Step 1

Given: Angular velocity = 2.10 x 10^3 rev/min To convert rev/min to Hz: 2.10 x 10^3 rev/min = 2.10 x 10^3 / 60 Hz = 35 Hz Angular velocity (ω) = 2πf = 2π x 35 = 219.8 rad/s Show more…

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The wheel rotates at a constant rate of 2.10 x 10^3 rev/min. (a) What is its angular velocity in radians per second? (Enter the magnitude) 219.8 rad/s (b) Through what angle does it turn in 32 s? Express the solution in radians and degrees. In radians: 122.76 rad. In degrees: 7033.60 degrees.