Question

Wheel Spinner The wheel spinner shown here is spun twice. Part 1 of 4 Find the total number of outcomes in the sample space. Total number of outcomes in the sample space \( = \) \( \square \) 25 Part 2 of 4 Determine the probability of an odd number on the first spin and an even number on the second spin (Note: 0 is considered even). \[ P(\text { odd then even })=\frac{6}{25} \] Part: 2 / 4 Part 3 of 4 Determine the probability of a sum that is odd. \[ P(\text { odd sum })=\square \]

          Wheel Spinner The wheel spinner shown here is spun twice.

Part 1 of 4

Find the total number of outcomes in the sample space.
Total number of outcomes in the sample space \( = \) \( \square \) 25

Part 2 of 4

Determine the probability of an odd number on the first spin and an even number on the second spin
(Note: 0 is considered even).
\[
P(\text { odd then even })=\frac{6}{25}
\]

Part: 2 / 4

Part 3 of 4

Determine the probability of a sum that is odd.
\[
P(\text { odd sum })=\square
\]

Wheel Spinner The wheel spinner shown here is spun twice.

Part 1 of 4

Find the total number of outcomes in the sample space.
Total number of outcomes in the sample space = □ 25

Part 2 of 4

Determine the probability of an odd number on the first spin and an even number on the second spin
(Note: 0 is considered even).

P( odd then even )=(6)/(25)

Part: 2 / 4

Part 3 of 4

Determine the probability of a sum that is odd.

P( odd sum )=□

Added by Margaret P.

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