Question

When 0.070 moles of NO reacts according to the reaction below, what is the change in energy? 4 NO(g) + 6 H2O(l) → 4 NH3(g) + 5 O2(g) ΔH = -1172 kJ Report your answer, kJ, with one decimal place including a negative if applicable.

          When 0.070 moles of NO reacts according to the reaction below, what is the change in energy?
4 NO(g) + 6 H2O(l) → 4 NH3(g) + 5 O2(g)     ΔH = -1172 kJ

Report your answer, kJ, with one decimal place including a negative if applicable.
        
Show more…

Added by Danielle R.

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
When 0.070 moles of NO reacts according to the reaction below, what is the change in energy? 4 NO(g) + 6 H2O(l) → 4 NH3(g) + 5 O2(g) ΔH = -1172 kJ Report your answer, kJ, with one decimal place including a negative if applicable.
Close icon
Play audio
Feedback
Powered by NumerAI
Danielle Fairburn Ivan Kochetkov
Jennifer Stoner verified

David Collins and 71 other subject Chemistry 101 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
4-nh3-g-5-o2-g-4-no-g-6-h2o-g-ho-90548-kj-calculate-the-overall-change-in-enthalpy-when-1200-grams-of-nh3-g-reacts-with-excess-o2-g-be-sure-to-include-the-correct-sign-enthalpy-change-answer-99595

4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (g) ΔHº = -905.48 kJ Calculate the overall change in enthalpy when 12.00 grams of NH3 (g) reacts with excess O2 (g). [Be sure to include the correct sign.] Enthalpy change: Answer kJ How many grams of H2O (g) are produced when the reaction above releases 397.2 kJ of heat energy. Answer grams of H2O (g)

David C.

2calculate-h-for-the-reaction-4-nh3g5-o2g4-nog6-h2ogfrom-the-following-datad253marks-n2-g-o2-g-2-no-g-h-1805-kj-ng3h2g-2nh3g-h-918-kj-2-h2-g-o2g-2-h2o-g-h-4836-kj-96004

Calculate ΔH for the reaction 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g), from the following data. N2(g) + O2(g) → 2 NO(g) ΔH = -180.5 kJ N2(g) + 3H2(g) → 2 NH3(g) ΔH = -91.8 kJ 2 H2(g) + O2(g) → 2 H2O(g) ΔH = -483.6 kJ

Dominique Jan T.

calculate-the-enthalpy-change-for-the-reaction-below-given-the-standard-heat-of-combustion-for-ammonia-nh3-is-226-kjmol-4nh3-g-5o2g-4nog-6h2og-13157

Calculate the enthalpy change for the reaction below, given that the standard heat of combustion for ammonia, NH3, is -226 kJ/mol. 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)

Ivan K.


*

Recommended Textbooks

-
Chemistry: Structure and Properties

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition
achievement 1,855 solutions
Chemistry The Central Science

Chemistry The Central Science

Theodore L. Brown 14th Edition
achievement 1,539 solutions
Chemistry

Chemistry

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste 10th Edition
achievement 1,220 solutions

*

Transcript

-
00:01 If our balanced chemical reaction is 4 moles of ammonia, nh3, reacting with 5 moles of o2 to produce 4 moles of no and 6 moles of h2o with a delta h of negative 905 .48 kilojoules for the reaction as written, then if we have 12 .00 grams of ammonia and sufficient oxygen, ammonia will be the limiting reactant.
00:37 We can convert the grams of ammonia into moles of ammonia using the molar mass of ammonia, 1 mole nh3 has a mass of 17 .0305 grams.
00:52 Then from the stoichiometry of the reaction, we see that when 4 moles of ammonia react, we release 905 .48 kilojoules.
01:05 So if just 12 moles react, we'll release, so it's negative, 159 .5 kilojoules of energy.
01:19 Then for the second question, it tells us that 397 .2 kilojoules of energy was released, so how many grams of water are produced? for this one, it'll be a unit conversion calculation again, but we'll start with the energy, negative 397 .2 kilojoules...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever