Question

When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040 m to 0.045 m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a distance of 0.15 m away from the rest position. The block is released at time t = 0 s and undergoes simple harmonic motion. What is the spring constant of the spring? N/m What is the amplitude of the motion? m What is the period of oscillation of the mass-spring system? s What is the speed of the block as it passes the rest position? m/s 0.20 kg

          When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040 m to 0.045 m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a distance of 0.15 m away from the rest position. The block is released at time t = 0 s and undergoes simple harmonic motion.
What is the spring constant of the spring? N/m
What is the amplitude of the motion? m
What is the period of oscillation of the mass-spring system? s
What is the speed of the block as it passes the rest position? m/s
0.20 kg
        
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When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040 m to 0.045 m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a distance of 0.15 m away from the rest position. The block is released at time t = 0 s and undergoes simple harmonic motion.
What is the spring constant of the spring? N/m
What is the amplitude of the motion? m
What is the period of oscillation of the mass-spring system? s
What is the speed of the block as it passes the rest position? m/s
0.20 kg

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040 m to 0.045 m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a distance of 0.15 m away from the rest position. The block is released at time t = 0 s and undergoes simple harmonic motion. What is the spring constant of the spring? N/m What is the amplitude of the motion? m What is the period of oscillation of the mass-spring system? s What is the speed of the block as it passes the rest position? m/s 0.20 kg
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Transcript

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0:00 Hi.
00:01 Here in this given problem, mass of the block which is initially suspended with a vertical spring, that is m is equal to 0 .20 kilogram.
00:20 Extension in the vertical spring, that is delta x, let it be delta l.
00:41 Delta l that is the final length 0 .045 meter minus the initial length 0 .040 meter and it comes out to be equal to 0 .005 meter...
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