00:01
All right, so here we're going to be solving for the new freezing point of a solution that consists of a solute dissolved in the solvent can for.
00:09
In order to solve this problem, you're going to need some extra information about your solvent, which can be found in figure 2 .3 on page 424 of your textbook.
00:21
And so what we know is that we have a sawute.
00:23
They don't tell us if it's an electrolytes.
00:25
We're going to assume that it just has a vanhoff i factor of one.
00:28
Then from figure 2 .3, we learned that the freezing point, depression constant, of kamport, is 39 .7.
00:37
Then finally, we want to substitute in for the molality, which is the moles of solute per kilograms of solvent.
00:44
So for our solute, we're told that we have 1 .5 grams, and what we want to do is to convert our grams to moles using the molar mass that they provide, 125 grams per one mole.
00:57
So we'll take 1 .5 and divide our grams.
00:59
By 125 and our answer will be 0 .012 moles...