00:01
Hi, in this question we have to calculate the empirical formula of copper oxide.
00:05
Now, copper plus o2 gives a copper oxide like this.
00:16
Now, we are given with mass of copper as cu and, that is 2 .50 and mass of copper oxide is 2 .80.
00:26
Now using the law of conservation of mass, that is, mass of reactants in a reaction, is always equal to.
00:35
To the mass of products.
00:40
So, we can say that mass of copper plus oxygen is equal to mass of cox -o -y formed.
00:54
So, from here we can calculate the mass of oxygen is equal to mass of cox -o -y minus mass of copper -reacted, that is equal to 2 .5.
01:12
1 .81 gram minus 2 .50 gram.
01:17
Now this is equal to 0 .31 gram.
01:21
Now first we have to calculate the moles of each.
01:29
So, moles of copper firstly are calculated as mass divided by molar mass.
01:34
So mass is 2 .50 gram divided by molar mass is 64 gram per mole...