00:01
So in this question, we're going to be using the equation q equals mcat, as i like to call it, and setting q1 and q2 equal to each other and finding the answer.
00:11
So overall, we're looking to find the heat of fusion per gram of solid a.
00:17
And you can use the principle of conservation of energy.
00:20
The heat lost by the liquid as it cools down is equal to the heat gained by the solid as it melts.
00:26
The formula to calculate heat transfer is q equals mc delta t, where q is heat, energy, and joules, m is mass in grams, c is specific heat in joules per gram celsius, and delta t is change in temperature in celsius.
00:46
So let's break it down.
00:49
Number one, we want the heat lost by the liquid as it cools down.
00:59
So we're going to get q1 equals 62 .7 grams times 0 .798 joules per gram celsius times 35 .0 celsius minus 51 .2 celsius.
01:32
Next, we want our heat gained by the solid as it melts or melting...