00:01
Hi there, here we have to solve the given problem.
00:03
First of all, we have to write down the balance reaction between the chemicals.
00:09
Iron cl3 reacts with 3 moles of sodium hydroxide, and it forms iron hydroxide and 3 moles of sodium chloride.
00:28
Iron hydroxide is solid and the rest are soluble in water.
00:35
Now we have to identify limiting and excess reagents.
00:43
So to do this, we have to calculate number of most of iron chloride in the mixture and number of most of sodium hydroxide in the mixture.
01:03
So number of moles of iron chloride equals to its mass divided by the molar mass.
01:11
And so we have to check it up.
01:32
That is 162 grams per mole.
01:36
Mass of sodium hydroxide is 30 .0 grams per mole so let's calculate now we can calculate this numbers and now let's calculate the ratio of sodium hydroxide over iron chloride that equals to 3 .2 which is more than 3 that is theoretical that's why sodium hydroxide is the excess reactant and iron chloride is a limiting reactant.
03:12
So let me write it down here.
03:24
Now let's calculate the theoretical yield of sodium chloride...