Question

When a 0.25000 g of an unknown liquid hydrocarbon containing only carbon and hydrogen was burned in a combustion apparatus two products were collected: 8.4510 x10-1 g of CO2 and 1.7297 x 10-1 g of H2O. 5.1.1 Use the information in 5.1 above to determine the empirical formula and empirical mass of the unknown liquid hydrocarbon.

Name: when a 025000 g of an unknown liquid hydrocarbon containing only carbon and hydrogen was burned in a combustion apparatus two products were collected 84510 x10 1 g of co2 and 17297 x 10 1 g 44075
Uploaded: 2022-09-30T07:36:55-08:00
Duration: 2 min 16 s
Channel: Sri K
Description: when a 025000 g of an unknown liquid hydrocarbon containing only carbon and hydrogen was burned in a combustion apparatus two products were collected 84510 x10 1 g of co2 and 17297 x 10 1 g 44075

          When a 0.25000 g of an unknown liquid hydrocarbon containing only carbon and hydrogen was burned in a combustion apparatus two products were collected: 8.4510 x10-1 g of CO2 and 1.7297 x 10-1 g of H2O. 5.1.1 Use the information in 5.1 above to determine the empirical formula and empirical mass of the unknown liquid hydrocarbon.

Added by Andr-S L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

09/30/2022

Step 1

- The molar mass of CO2 is 44.01 g/mol. - Moles of CO2 = mass of CO2 / molar mass of CO2 - Moles of CO2 = 0.84510 g / 44.01 g/mol = 0.0192 mol Show more…

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When a 0.25000 g of an unknown liquid hydrocarbon containing only carbon and hydrogen was burned in a combustion apparatus two products were collected: 8.4510 x10-1 g of CO2 and 1.7297 x 10-1 g of H2O. 5.1.1 Use the information in 5.1 above to determine the empirical formula and empirical mass of the unknown liquid hydrocarbon.