When a $3-\mathrm{kg}$ block is suspended from a spring, the spring is stretched a distance of $60 \mathrm{mm} .$ Determine the natural frequency and the period of vibration for a $0.2-\mathrm{kg}$ block attached to the same spring.
Added by Thomas K.
Step 1
81 \, \text{m/s}^2$, and $\Delta x = 0.06 \, \text{m}$. Plugging in the values, we get: $K = \frac{3 \cdot 9.81}{0.06} = 490.5 \, \text{N/m}$. ** Show more…
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