00:01
To calculate the initial temperature of the copper, we need to make the assumption that the heat lost by the copper will be equal to the heat gained, so it'll be positive, by the water.
00:12
We'll assume that the heat didn't go anywhere else, that all the heat lost by the copper went to the water.
00:20
So q of the copper will be equal to the specific heat of copper, 0 .384, joules per gram, degrees celsius.
00:31
Multiplied by the mass of the copper, they tell us that 248 grams of copper was warmed up and dropped into the water.
00:44
And then it'll be t final minus t initial for the change in temperature.
00:50
The final temperature was measured to be 39 .9 degrees celsius.
00:57
We'll then subtract off the initial temperature that we need to calculate.
01:03
That will be equal to q of water, which will be specific heat of water, 4 .184, joules per gram degree celsius, multiplied by the mass of water, this was given at 390 grams, multiplied by its change in temperature.
01:24
Its final temperature was 39 .9 also.
01:28
And its initial temperature was given at 22 .6 degrees celsius...