00:01
We'd like to find the drag force on the cylinder, or formula for the drag force on the cylinder.
00:08
Okay.
00:12
Now, we can apply the steady flow continuity equation between our entrance and our exit.
00:19
We have 0 is equal to 2, row u, da, minus the integral over 1, row uda.
00:28
We can substitute our values.
00:30
We have 0 is equal to 2 times the integral from 0 to l, of row u over 2 1 plus y over l b d y minus row u b times h since it's uniform h is equal to 2 h so now our expression you can rewrite our expression zero is equal to two the integral from zero to l of row u over 2 1 plus y over l b d y minus two row u b b b h now our fb is equal to negative f drag.
01:13
So we can substitute this now.
01:15
We have 2, the integral from 0 to l, u over 2, 1 plus y over l, row u over 2, 1 plus y over l b, d .y, minus 2 u squared row b, h equal to negative f drag...