Question

When choosing the resistor value for this circuit, we placed an upper bound on the diode current (25 mA) and used the max power supply voltage (5 V) to calculate a minimum resistance (5 V/25 mA = 200 ohm) to prevent damage to the LED. In the lab, you actually found that the diode current at a 5 V supply voltage was less than 25 mA! Explain why this is the case. (Note that this reduction in current is not only from rounding 200 ohms to 220 ohms) ANSWER HERE In circuit theory, we sometimes make the simplification that once a diode is forward biased or "on", the voltage across a diode does not change?. Using the Vd you measured at a 5 V supply voltage, calculate the resistor value to place the diode current at exactly 25 mA. Show your work: ? This is called the Constant-Voltage Drop model for a diode (covered in ECE 115A). ANSWER HERE

          When choosing the resistor value for this circuit, we placed an upper bound on the diode current (25 mA) and used the max power supply voltage (5 V) to calculate a minimum resistance (5 V/25 mA = 200 ohm) to prevent damage to the LED. In the lab, you actually found that the diode current at a 5 V supply voltage was less than 25 mA! Explain why this is the case. (Note that this reduction in current is not only from rounding 200 ohms to 220 ohms)

ANSWER HERE

In circuit theory, we sometimes make the simplification that once a diode is forward biased or "on", the voltage across a diode does not change?. Using the Vd you measured at a 5 V supply voltage, calculate the resistor value to place the diode current at exactly 25 mA. Show your work:

? This is called the Constant-Voltage Drop model for a diode (covered in ECE 115A).

ANSWER HERE

When choosing the resistor value for this circuit, we placed an upper bound on the diode current (25 mA) and used the max power supply voltage (5 V) to calculate a minimum resistance (5 V/25 mA = 200 ohm) to prevent damage to the LED. In the lab, you actually found that the diode current at a 5 V supply voltage was less than 25 mA! Explain why this is the case. (Note that this reduction in current is not only from rounding 200 ohms to 220 ohms)

ANSWER HERE

In circuit theory, we sometimes make the simplification that once a diode is forward biased or "on", the voltage across a diode does not change?. Using the Vd you measured at a 5 V supply voltage, calculate the resistor value to place the diode current at exactly 25 mA. Show your work:

? This is called the Constant-Voltage Drop model for a diode (covered in ECE 115A).

ANSWER HERE

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