Question

When $f(x) = x^3 + 3x^2 - 5ax - 6$ is divided by $x + 1$, the remainder is 6. Find the value of $a$. Solve $(\sin x + \cos x)^2 = \frac{3}{2}$, for $0 \le x \le 2\pi$. If $v(x) = \frac{x - 3}{x + 8}$, $w(x) = 4x^2 + 5x - 13$, find $v^{-1}[w(6)]$. Solve $2 \sin 2x = 3 \tan x$ for $90^\circ < x < 180^\circ$. The remainder, when $ax^3 - 4x^2 - 3x$ is divided by $x + 1$ is half of that when it is divided by $x - 2$. Find the value of $a$ and hence find the remainder when it is divided by $x - 3$.

Name: when fx x3 3x2 5ax 6 is divided by x 1 the remainder is 6 find the value of a solve sin x cos x2 frac32 for 0 le x le 2pi if vx fracx 3x 8 wx 4x2 5x 13 find v 1w6 solve 2 sin 2x 3 tan x for 25537
Uploaded: 2020-08-29T04:58:39-08:00
Duration: 2 min 46 s
Channel: Suman Saurav Thakur
Description: when fx x3 3x2 5ax 6 is divided by x 1 the remainder is 6 find the value of a solve sin x cos x2 frac32 for 0 le x le 2pi if vx fracx 3x 8 wx 4x2 5x 13 find v 1w6 solve 2 sin 2x 3 tan x for 25537

          When $f(x) = x^3 + 3x^2 - 5ax - 6$ is divided by $x + 1$, the remainder is 6. Find the value of $a$.
Solve $(\sin x + \cos x)^2 = \frac{3}{2}$, for $0 \le x \le 2\pi$.
If $v(x) = \frac{x - 3}{x + 8}$, $w(x) = 4x^2 + 5x - 13$, find $v^{-1}[w(6)]$.
Solve $2 \sin 2x = 3 \tan x$ for $90^\circ < x < 180^\circ$.
The remainder, when $ax^3 - 4x^2 - 3x$ is divided by $x + 1$ is half of that when it is divided by $x - 2$. Find the value of $a$ and hence find the remainder when it is divided by $x - 3$.

$when fx x3 3x2 5ax 6 is divided by x 1 the remainder is 6 find the value of a solve sin x cos x2 frac32 for 0 le x le 2pi if vx fracx 3x 8 wx 4x2 5x 13 find v 1w6 solve 2 sin 2x 3 tan x for 25537$

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