00:01
Hi, in this question they're saying that when landing on a carrier a 10 ,000 pound airplane, so weight is given as 10 ,000 pounds, which is given a deacceleration of 3 grams.
00:18
So we have been given the value of a as 3g by means of a cable engaged by an arresting hook as we can see in this figure.
00:30
So in part a, we have to find the tension in the cable and the wheel reaction are.
00:36
So first of all, force on the plane that is f can be calculated as mass into acceleration, where mass is given as w by g into a.
00:48
So we can calculate this as 10 ,000 divided by g into 3 times g, which gives the value of force f as 30 ,000 pounds.
01:05
So now if we resolve the horizontal forces, then sum of forces on x direction will be equals to zero or t cos 10 degree minus 30 ,000 will be equals to zero, which gives the value of tension t in the cable as equals to 30462 .79 pounds.
01:37
Now, if we resolve the vertical forces, then we can write that summation of force in vertical direction will be zero or r minus w minus t sin of 10 degree will be zero.
01:52
So here we have to calculate the value of r...