When light strikes the surface between two materials from above, the Brewster angle is $65.0^{\circ} .$ What is the Brewster angle when the light enconters the same surface from below?
Added by Samuel M.
Step 1
Given that the Brewster angle is $65.0^\circ$, we have $\tan(65.0^\circ) = \frac{n_2}{n_1}$. Solving for $\frac{n_2}{n_1}$, we get $\frac{n_2}{n_1} = 2.144$. Show more…
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