00:01
Hi, so in this question it says that neely is hanging through a clothes line.
00:05
So this is our clothes line from point a to point b and point c.
00:10
This is our clothes line and she is hanging using one hand through this point b.
00:15
And she is not hanging at the centre but the rope can be divided into two parts.
00:22
So we have side a and side b.
00:25
So side a is the shorter length of the rope.
00:32
And side b corresponds to the longer length of the rope.
00:38
Now since she is hanging through this point, so her weight will be acting downwards at this point.
00:45
So we have to find out out of the two sides, a and b, which one will we have the higher tension? so we have to find out higher tension out of a or b.
00:59
So let us call the two tensions as t -a and t -b.
01:03
And they will be acting upwards like this so what we need to know is find out these magnitudes and find out which one will be higher so what we will do here is we will just qualitatively find the answer by using the parallelogram method for the resultant of two forces so what we can do here is so what is happening this w weight is acting downwards since she is in equilibrium so the all three forces should sum up to be equal to zero so the result resultant of t a and tb.
01:39
So their resultant t equals to t a plus t b the vector sum of these this should be equal and opposite to the w force the weight of neely acting downwards.
01:53
So if we let us draw the lines like this this is the vertical direction and this is the horizontal direction here...