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In this problem we are given that there are two events a and b, such that the probability of the event a, this is equal to 1 by 3.
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Probability of the event b, that's equal to 1 by 2, and the probability of a union b, that is equal to 3 by 4.
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And we are required to first determine the probability of a intersection b.
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Well, to get this, we simply use this formula and put the values, of the probabilities.
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So doing that, we will get 3 by 4 equal to 1 by 3 plus 1 by 2 minus probability of a intersection b.
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And after we solve this equation, we will get the probability of a intersection b as 1 by 12.
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And in the next part, we have to determine the value of the probability of a complement union b.
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And to get this, we use this formula once again, but replace a with a complement...