00:03
This is the answer to chapter 15, problem number nine from the smith organic chemistry textbook.
00:10
And this problem asks which carbon hydrogen bond in each compound is most readily broken during radical halogenation.
00:19
And so it's going to be the weakest carbon hydrogen bond in each alkan that will be the most readily cleaved.
00:27
And we can think about this.
00:30
Well, we can think about this in terms of if we were to be making a carbocation, which would be our most stable carbocation.
00:42
And so that is going to be the hydrogen that's going to be most easily cleat.
00:47
So in a, we have several primary carbons, one secondary carbon, and one tertiary carbon.
00:59
And so the tertiary carbon is going to, well, that would form the best carbocadion.
01:07
And so it'll form the most stable radical as well.
01:11
And so that hydrogen will be the most easily cleep.
01:15
So in b, we have, and here i guess i'll write tertiary.
01:23
Okay...