When rolled down a mountainside at 7.0 m/s, the horizontal component of its velocity vector was 1.8 m/s. What was the angle of the mountain surface above the horizontal? 75° 33° 57° 15°?
Added by Jennifer S.
Step 1
Step 1: The horizontal component of velocity is given by \(V_x = V \cdot \sin(\theta)\), where \(V\) is the magnitude of the velocity and \(\theta\) is the angle of inclination. Show more…
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